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4. Algebraic Solutions of Linear Systems

Algebra problems With Solutions Example 1: Solve, (x-1)2 = [4√ (x-4)]2 Solution: x 2 -2x+1 = 16 (x-4) x 2 -2x+1 = 16x-64 x 2 -18x+65 = 0 (x-13) (x-5) = 0 Hence, x = 13 and x = 5. Algebra Problems

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A linear algebraic equation is nice and simple, containing only constants and variables to the first degree (no exponents or fancy stuff). To solve it, simply use multiplication, division, addition, and subtraction when necessary

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Given a general quadratic equation of the form ax²+bx+c=0 with x representing an unknown, with a, b and c representing constants, and with a ≠ 0, the quadratic formula is: x= (-b±√ (b²-4ac))/2a

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