Algebraic solution

4. Algebraic Solutions of Linear Systems

Algebra problems With Solutions Example 1: Solve, (x-1)2 = [4√ (x-4)]2 Solution: x 2 -2x+1 = 16 (x-4) x 2 -2x+1 = 16x-64 x 2 -18x+65 = 0 (x-13) (x-5) = 0 Hence, x = 13 and x = 5. Algebra Problems

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A linear algebraic equation is nice and simple, containing only constants and variables to the first degree (no exponents or fancy stuff). To solve it, simply use multiplication, division, addition, and subtraction when necessary

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Solution in radicals

Given a general quadratic equation of the form ax²+bx+c=0 with x representing an unknown, with a, b and c representing constants, and with a ≠ 0, the quadratic formula is: x= (-b±√ (b²-4ac))/2a

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To determine what the math problem is, you will need to look at the given information and figure out what is being asked. Once you know what the problem is, you can solve it using the given information.

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Algebraic solution

4. Algebraic Solutions of Linear Systems

Algebraic Equations

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Algebraic solution

Solution in radicals