So, angle of depression from point B is 45° and Height = BC = 10 m BX is the horizontal Now, we need to find the distance of point A from the building Now, lines BX and AC
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The angle of depression, ∠ SPR = 60° So, The angle of elevation, ∠ QRP = Angle of depression, ∠ SPR = 60°. Now, in right triangle PQR, QR = 100m ∠ R = 60° PQ = h (in m) Let ∠ R = θ = 60° We
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