Cartesian equation of a circle example. Example : Find the centre and the radius of the circle x^2 + y^2 + 8x + 10y – 8 = 0. Solution : The given equation is: (x^2 + 8x) + (y^2 + 10y) = 8. On

Example 1: Write the equation of the line passing through the points (3, 4, 2), and (5, -2, 4), in cartesian form.. Solution: The given two points are a =\((a_1, a_2, a_3)\) = (3, 4, 2), and b =

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Cartesian equation \text {E: } 2x-2y+4z=6 E: 2x− 2y+4z = 6 ! Remember With the cartesian form \text {E: } ax+bx+cz=d E: ax+bx+cz = d a normal vector can always be read off directly: \vec

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x= (y-2) 2 +1 Replace t into x. x=y²-4y+4+1. x=y²-4y+5. Therefore x=y²-4y+5 is the Cartesian equation. The equation is for a parabola and in the rectangle terms it can be seen