It is an Oblique Asymptote when: as x goes to infinity (or −infinity) then the curve goes towards a line y=mx+b (note: m is not zero as that is a Horizontal Asymptote). Example: (x 2 −3x)/ (2x−2) The graph of (x 2 -3x)/ (2x-2) has: A
asymptotes\:y=\frac{x^2+x+1}{x} asymptotes\:f(x)=x^3; asymptotes\:f(x)=\ln (x-5) asymptotes\:f(x)=\frac{1}{x^2} asymptotes\:y=\frac{x}{x^2-6x+8} asymptotes\:f(x)=\sqrt{x+3}
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1) The location of any vertical asymptotes. 2) The location of any x-axis intercepts. Here what the above function looks like in factored form: y = x +2 x +3 y = x + 2 x + 3 Once the original
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!The vertical asymptotes of a function can be found by examining the factors of the denominator that are not common with the factors of the numerator. The vertical asymptotes occur at the zeros of these factors. Given a rational function, we can identify the vertical asymptotes by following these steps: Step 1:Factor t See more
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