So the eigenspace that corresponds to the eigenvalue minus 1 is equal to the null space of this guy right here It's the set of vectors that satisfy this equation: 1, 1, 0, 0. And then you have v1
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The basis of an eigenspace is the set of linearly independent eigenvectors for the corresponding eigenvalue. The cardinality of this set (number of elements in it) is the dimension of the
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