The coordinates of the center \(O = (x, y) = (-2, 1)\) The coordinate geometry formula for midpoint of the line is: \[ (x, y) = \left(\dfrac{x_1 + x_2}{2}, \dfrac{y_1 + y_2}{2}\right) \] Applying this we have the following calculations.
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Taking squares on both sides. (√145)2 = (√a2 + 12a + 117)2. a2 + 12 a + 117 - 145 = 0. a2 + 12 a - 28 = 0. (a + 14) (a - 2) = 0. a = -14 (or) a = 2. So, the missing coordinates are -14 or 2. Apart
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