For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log (a)=\log (b) log(a) =log(b) then a a must equal b b \frac {x+1} {x-1}=1000 x −1x +1 = 1000
log(3x−2)−log(2) = log(x+4) log(3x−2 2) = log(x+4) Apply the quotient rule of logarithms. 3x−2 2 = x+4 Apply the one-to-one property. 3x−2 = 2x+8 Multiply both sides of the equation by 2. x = 10 Subtract 2x and add 2.
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