Example: Solve 5x 2 + 6x + 1 = 0. Coefficients are: a = 5, b = 6, c = 1. Quadratic Formula: x = −b ± √ (b2 − 4ac) 2a. Put in a, b and c: x = −6 ± √ (62 − 4×5×1) 2×5. Solve: x = −6 ± √ (36− 20) 10. x = −6
The quadratic function f(x) = a x 2 + b x + c can be written in vertex form as follows: f(x) = a (x - h) 2 + k The discriminant D of the quadratic equation: a x 2 + b x + c = 0 is given by D = b 2 - 4 a c If D = 0 , the quadratic equation a x 2 + b x
Add them up and the height h at any time t is: h = 3 + 14t − 5t 2. And the ball will hit the ground when the height is zero: 3 + 14t − 5t 2 = 0. Which is a Quadratic Equation ! In Standard Form it looks like: −5t 2 + 14t + 3 = 0. It looks even
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