\log _2(x+1)=\log _3(27) \ln (x+2)-\ln (x+1)=1 \ln (x)+\ln (x-1)=\ln (3x+12) 4+\log _3(7x)=10 \ln (10)-\ln (7-x)=\ln (x) \log _2(x^2-6x)=3+\log _2(1-x)

Solve the equation for x step-by-step. full pad ». x^2. x^ {\msquare} \log_ {\msquare} \sqrt {\square} \nthroot [\msquare] {\square} \le. \ge.

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